1.

A neutron star has a density equal to that of nuclear matter (2.8×10^17 kg m^-3). Assume the star to be spherical, find the radius of the neutron star whose mass is 4.0×10^10 kg (twice the mass of the sun) .

Answer»

Given,
density of neutron STAR,
p = 2.8 \times {10}^{17} kg \: {m}^{ - 3}
MASS of neutron star,
m = 4.0 \times {10}^{10} kg
density(p) is given by,

p = \frac{m}{v}
p = \frac{m}{ \frac{4}{3}\pi \: {r}^{3} } \: \: \: \: \: \: \:
because,
(v = \frac{4}{3} \pi \: {r}^{3} )
{r}^{3 } = \frac{3m}{4\pi \: p}
{r}^{3 } = \frac{3 \times 4.0 \times {10}^{10} }{4 \times 3.14 \times 2.8 \times \ {10}^{17} }
after CALCULATION,
{r}^{3} = 0.341 \times {10}^{ - 7}
r = 0.32 \times {10}^{ - 2} m
hope this help........:)


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