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A neutron having kinetic energy `E_(0)` collides with singly ionised He atom at rest and move along initial direction. Which of the following statement(s) is/are true for the above mentioned collision.A. Collision will be perfectly inelastic if `E_(0)=17eV`B. Collision will be perfectly inelastic is `E_(0)=8.16eV`C. If `E_(0)=` then ploton of wavelength `lamda=500m` is observed just after the collision if `E_(0)=8.16eV`.D. Perfectly elastic collision is not possible. |
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Answer» Correct Answer - A::B::D `mv_(0)=(4m+m)v` `v=(v_(0))/5` `1/2mv_(0)^(2)=1/2.(5m).(v_(0)^(2))/25+/_E` `1/2 mv_(0)^(2)-1/2 . (v^(2))/25m=/_E` `implies 1/2 mv_(0)^(2) {4/5}=/_E` `1/2 mv_(0)^(2)=5/4/_E` `/_E=13.6` `/_E=13.6{1- 1/6}=3/4/ (13.6)` `1/2 mv_(0)^(2)=5/4xx13.6 3/5xx13.6` `=17 eV, 8.16 eV` |
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