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A neutral atom `(A)` is converted to `(A)` by the following process `Aoverset(E_(1))underset(-e^(-1))rarrA^(+)overset(E_(2))underset(e^(-))rarrA^(+2)overset(E_(3))underset(e^(-))rarrA^(3+)` The correct order of of `E_(1)`, `E_(2)` and `E_(3)` energies is `:-`A. `E_(1)ltE_(2)ltE_(3)`B. `E_(1)gtE_(2)gtE_(3)`C. `E_(1)=E_(2)=E_(3)`D. `E_(1)gtE_(2)ltE_(3)` |
| Answer» Correct Answer - A | |