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A network of resistor is connected to a 16 V battery with internal resistance of `1 Omega`, a shown in fig. (a) complete the equivalent resistance of the network. |
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Answer» The network is a simple series and parallel combination of resistors. First the two `4 Omega` resistors in parallel are equivalent to a resistor. `= [(4 xx 4)//(4 + 4)]Omega = 2 Omega` In the same, way, the `12 Omega` and `6 Omega` resistors in parallel are equivalent to a resistor of `[(12 xx 6)//(12 + 6)] Omega = 4 Omega` The equivalent resistance R of the network is obtained by combining these resistors (`2 Omega` and `4 Omega` with `1 Omega` in series, that is `R = 2 Omega + 4 Omega + 1 Omega = 7 Omega` |
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