1.

A moving particle of mass m makes a head on elastic collision with a particle of mass 2m

Answer»

Answer:

ANSWER

Given : m

1

=m m

2

=2m u

2

=0 u

1

=u

Let the velocity of mass m after the collision be v

1

.

Using v

1

=

m

1

+m

2

(m

1

−em

2

)u

1

+(1+e)m

2

u

2

v

1

=

m+2m

(m−1×2m)u+(1+1)2m(0)

=

3

u

Thus final kinetic energy of m

1

, E

1

′

=

2

1

MV

1

2

=

2

1

m×

9

u

2

=

18

1

mu

2

Initial kinetic energy of m

1

, E

1

=

2

1

mu

2

Fraction loss in K.E of m

1

,

E

1

ΔK.E

=

2

1

mu

2

2

1

mu

2

−

18

1

mu

2

=

9

8

SOLUTION


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