A moving coil galvanometer has a coil with 175 turns and area 1 cm²It

1.	A moving coil galvanometer has a coil with 175 turns and area 1 cm²It uses a torsion band of torsion constant 10⁻⁶ N – m/rad. The coil is placed in a magnetic field B parallel to its plane. The coil deflects by 1⁰ for a current of 1 mA. The value of B (in Tesla) is approximately:-(A) 10⁻³(B) 10⁻¹(C) 10⁻⁴(D) 10⁻²
Answer» ${\red{\huge{\underline{\mathbb{Moving coil Galvanometer:-}}}}}$ The moving engagement was devised by Kelvin and later on modified by D' Arsonaval . this is used for detection and measurement of small electric current. Theory : Torque on the coil = NIAB where ,n = number of turns in the coil A = area and B = magnetic FIELD induction of radial magnetic field in which the call is suspended. ↪due to the torque , the coil ROTATES. no restoring torque is developed in the suspension wire. in EQUILIBRIUM, deflecting couple= restoring torque niAB = C∅ $\huge{\blue{\boxed{\boxed{\boxed{\pink{\underline{\underline{\mathfrak{\red{♡ĂnSwer♡}}}}}}}}}}$ Given : i = 1 mA ∅ = 1° = π/180 radian A = 1 cm² $C = 10 {}^{ - 6} N \: m / \: radian$ n = 175 turns C∅= niAB put the given values $10 {}^{ -6} \times \frac{\pi}{180} = 10 {}^{ - 3} \times 10 {}^{ - 4} \times 175 \times B$ $B = 10 {}^{ - 3} \: tesla$ correct option a) Follow me!

A moving coil galvanometer has a coil with 175 turns and area 1 cm²It uses a torsion band of torsion constant 10⁻⁶ N – m/rad. The coil is placed in a magnetic field B parallel to its plane. The coil deflects by 1⁰ for a current of 1 mA. The value of B (in Tesla) is approximately:-(A) 10⁻³(B) 10⁻¹(C) 10⁻⁴(D) 10⁻²

Answer»

${\red{\huge{\underline{\mathbb{Moving coil Galvanometer:-}}}}}$

The moving engagement was devised by Kelvin and later on modified by D' Arsonaval . this is used for detection and measurement of small electric current.

Theory :

Torque on the coil = NIAB

where ,n = number of turns in the coil

A = area

and B = magnetic FIELD induction of radial magnetic field in which the call is suspended.

↪due to the torque , the coil ROTATES. no restoring torque is developed in the suspension wire.

in EQUILIBRIUM,

deflecting couple= restoring torque

niAB = C∅

$\huge{\blue{\boxed{\boxed{\boxed{\pink{\underline{\underline{\mathfrak{\red{♡ĂnSwer♡}}}}}}}}}}$

Given : i = 1 mA

∅ = 1° = π/180 radian

A = 1 cm²

$C = 10 {}^{ - 6} N \: m / \: radian$

n = 175 turns

C∅= niAB

put the given values

$10 {}^{ -6} \times \frac{\pi}{180} = 10 {}^{ - 3} \times 10 {}^{ - 4} \times 175 \times B$

$B = 10 {}^{ - 3} \: tesla$

Theory :

correct option a)

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