A moving body is covering a distance directly proportional to the squa

1.	A moving body is covering a distance directly proportional to the square of time. The acceleration of the body is:A. increasing B. decreasing C. zero D. constant
Answer» We know that ,\(Distance\propto\,time^2\) ….1 Now, \(velocity=\frac{Distance}{Time}\) ….2 From equations 1 and 2, we get, Velocity \(\propto\)Time ….3 Now, we also know that, \(Acceleration=\frac{velocity}{Time}\) ….4 So, from equations 3 and 4, we get, \(Acceleration\propto\,time^0\) Acceleration = Constant Hence, option D is correct

A moving body is covering a distance directly proportional to the square of time. The acceleration of the body is:A. increasing B. decreasing C. zero D. constant

Answer»

We know that ,\(Distance\propto\,time^2\) ….1

Now, \(velocity=\frac{Distance}{Time}\) ….2

From equations 1 and 2, we get, Velocity \(\propto\)Time ….3

Now, we also know that, \(Acceleration=\frac{velocity}{Time}\) ….4

So, from equations 3 and 4, we get,

\(Acceleration\propto\,time^0\)

Acceleration = Constant

Hence, option D is correct