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A motorcyclist wants to drive on the vertical surface of a wooden well of radius 5m with a minimum speed of 5√5 The minimum value of coefficient of friction between the tyres and the wall of the well must be? |
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Answer» Frictional force = f = mg Centripetal Force = Contact force = N = mv² / r μ = f / N = mg / (mv2 / r) = rg / v² = (5 × 10) / (5√5)² = 50 / 125 = 0.4 Minimum coefficient of friction between the tyres and wall of the well must be 0.4 |
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