Saved Bookmarks
| 1. |
A motorcycle is being driven at a speed of 20m/s when breaks are applied to bring it to rest in five seconds. The deceleration produced in this case will be:a) +4m/s² b) -4m/s² c) +0.25m/s²d) -0.25m/s² |
|
Answer» SIMPLE is v=U-at . v is final velocity and u is initial velocity. a is ACCELERATION and t is the TIME. 0=20+5a. a=-4m/s2. |
|