A motorcar is moving with a velocity of 108 km/h and it takes 4 s to s

1.	A motorcar is moving with a velocity of 108 km/h and it takes 4 s to stop after the brakes are applied. Calculate the force exerted by the brakes on the motorcarDon't spam
Answer» $\huge\underline\mathcal\orange{QUESTION}$ A motorcar is MOVING with a VELOCITY of 108 km/h and it TAKES 4 s to stop after the brakes are applied. Calculate the FORCE exerted by the brakes on the motorcar. $\huge\underline\mathcal\red{ANSWER}$ $u = 108 \: km \: h \\ converting \: the \: units \\ u = 108 \times \frac{5}{18} = 30 \: m \: s \\$ $v = 0 \: m \: s \\ t = 4 \: sec \\ formula \:for \: acceleration \: \\ acc = \frac{v - u}{t} \\ inserting \: the \: values \\ acc = \frac{0 - 30}{4} = - 3.75 {m \: s}^{2} (retardation) \\$ $formula \: for \: force =f = ma \\ f = - 3.75 \times 1000=-7500 N$ $\huge\underline\mathcal\purple{BTS \: EXO}$

A motorcar is moving with a velocity of 108 km/h and it takes 4 s to stop after the brakes are applied. Calculate the force exerted by the brakes on the motorcarDon't spam

Answer»

$\huge\underline\mathcal\orange{QUESTION}$

A motorcar is MOVING with a VELOCITY of 108 km/h and it TAKES 4 s to stop after the brakes are applied. Calculate the FORCE exerted by the brakes on the motorcar.

$\huge\underline\mathcal\red{ANSWER}$

$u = 108 \: km \: h \\ converting \: the \: units \\ u = 108 \times \frac{5}{18} = 30 \: m \: s \\$

$v = 0 \: m \: s \\ t = 4 \: sec \\ formula \:for \: acceleration \: \\ acc = \frac{v - u}{t} \\ inserting \: the \: values \\ acc = \frac{0 - 30}{4} = - 3.75 {m \: s}^{2} (retardation) \\$

$formula \: for \: force =f = ma \\ f = - 3.75 \times 1000=-7500 N$

$\huge\underline\mathcal\purple{BTS \: EXO}$

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