A motor is used to deliver water through a pipe. Let the motor have a power P initially. To double the rate of flow of water through the pipe, the power is increased to P’. What is the value of P’/P?(a) 2(b) 4(c) 6(d) 8I got this question in class test.I would like to ask this question from Power in chapter Work, Energy and Power of Physics – Class 11

A motor is used to deliver water through a pipe. Let the motor have a

1.	A motor is used to deliver water through a pipe. Let the motor have a power P initially. To double the rate of flow of water through the pipe, the power is increased to P’. What is the value of P’/P?(a) 2(b) 4(c) 6(d) 8I got this question in class test.I would like to ask this question from Power in chapter Work, Energy and Power of Physics – Class 11
Answer» The correct answer is (d) 8 Easiest explanation: POWER = Force X Velocity = (Mass/Time) x Velocity^2 = Rate of flow x Velocity^2 Rate of flow = Area x Velocity Doubling the rate of flow will DOUBLE the velocity. P = Rate of flow x Velocity^2 P’ = (2 x Rate of flow) x (2 x Velocity) ^2 = 8P P/P’ = 8.

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