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A motor cycle and rider having a total weightW=1500N travels in a vertical plane following acurve of radius r=50m at a speed of 10m/sec.Compute the thrust exerted by the road as itpasses over the crest C on the curve as shownin the Fig. Assume g=10m/s2ans.1600N1500N1000N1200N |
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Answer»
In cases like these, the thrust (or normal) exerted by the road is the SUM or difference of the weight of the body and centripetal force. In this case,. thrust = weight - centripetal force = mg - m v^2 / R = 1500 - (1500/10) × ( 10^2 ) / 50 = 1500 - 150 × 100 / 50 = 1500 - 300 = 1200 N PS- The figure is not given and the question isn't as clear, but this is what I think the question is asking. Do TELL me if I'm wrong. |
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