A motor car of mass 20 quintal is moving with velocity of 60 km per ho

1.	A motor car of mass 20 quintal is moving with velocity of 60 km per hour by application of brakes is brought to rest in a distance of 3 kilometre find average force of resistance and newton
Answer» *GIVEN conditions ⇒* *Mass = 20 Quintal = 2000 kg.* *Initial Velocity = 60 km/hr.* *Distance covered before coming to rest = 3 km.* *Final Velocity = 0* *Using the Third's EQUATION of motion,* *v² - u² = 2aS* *⇒ (0)² - (60)² = 2(a)(3)* *⇒ a = -3600/6* *∴ a = -600 km/hr²* *Now, For the Force,* *Force = Mass × Acceleration.* *∴ Force = 2000 × -600* *= -12 × 10⁵ N.* *Negative sign shows that the force is acting in the Opposite direction.* *Hope it helps.*

A motor car of mass 20 quintal is moving with velocity of 60 km per hour by application of brakes is brought to rest in a distance of 3 kilometre find average force of resistance and newton

Answer»

GIVEN conditions ⇒

Mass = 20 Quintal = 2000 kg.

Initial Velocity = 60 km/hr.

Distance covered before coming to rest = 3 km.

Final Velocity = 0

Using the Third's EQUATION of motion,

v² - u² = 2aS

⇒ (0)² - (60)² = 2(a)(3)

⇒ a = -3600/6

∴ a = -600 km/hr²

Now, For the Force,

Force = Mass × Acceleration.

∴ Force = 2000 × -600

= -12 × 10⁵ N.

Negative sign shows that the force is acting in the Opposite direction.

Hope it helps.

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