a motor car of mass 1200 kg is moving along a straight line with a uni

1.	a motor car of mass 1200 kg is moving along a straight line with a uniform velocity of 90 km / h its velocity is slowed down to 18 km/ h in 4 sec by an unbalanced force calculate the accelaration and change in momentum also calculate the magnitude of the force required
Answer» m=1200kg u=90km/h =>90×5/18=25m/s v=18km/h =>18×5/18=5m/s t=4s Thus,acceleration of the body is------ a=(v-u)/t a=(5-25)/4 a=-20/4 a= -5m/s² Thus,change in momentum of the body is------ mv-mu 1200×5-1200×25 1200(5-25) 1200×(-20) -24000 KG m/s Thus,the magnitude of force required is------ F=ma F=1200×(-5) F= -6000N,or 6000N in the OPPOSITE direction.

a motor car of mass 1200 kg is moving along a straight line with a uniform velocity of 90 km / h its velocity is slowed down to 18 km/ h in 4 sec by an unbalanced force calculate the accelaration and change in momentum also calculate the magnitude of the force required

Answer»

m=1200kg

u=90km/h

=>90×5/18=25m/s

v=18km/h

=>18×5/18=5m/s

t=4s

Thus,acceleration of the body is------

a=(v-u)/t

a=(5-25)/4

a=-20/4

a= -5m/s²

Thus,change in momentum of the body is------

mv-mu

1200×5-1200×25

1200(5-25)

1200×(-20)

-24000 KG m/s

Thus,the magnitude of force required is------

F=ma

F=1200×(-5)

F= -6000N,or 6000N in the OPPOSITE direction.

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a motor car of mass 1200 kg is moving along a straight line with a uniform velocity of 90 km / h its velocity is slowed down to 18 km/ h in 4 sec by an unbalanced force calculate the accelaration and change in momentum also calculate the magnitude of the force required​

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a motor car of mass 1200 kg is moving along a straight line with a uniform velocity of 90 km / h its velocity is slowed down to 18 km/ h in 4 sec by an unbalanced force calculate the accelaration and change in momentum also calculate the magnitude of the force required