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A motor car is moving with velocity of 144 kmh-1 and it takes 5 sec to stop after the application of braking force . Assuming the total mass of the motorcar and passenger as 1800kg , calculate the force exerted by the brakes on the motor car |
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Answer» Explanation:u = 108 km/h => 108×5/18 => 6×5 => 30 m/sv = 0m/st = 4sectherefore , a = (v-u)/t=>a = (0-30)/4=> a = -30/4 => -7.5 m/s²force = mass × accelerationforce = 1000 kg × (-7.5) m/s²force = -7500 kg m/s²=> force = -7500 Nnegative SIGN denotes opposing forceIF IT HELPSPLZ MARK IT AS BRAINLIEST |
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