A motor car is moving with a velocity of 108 km/h and it takes 4s to s

1.	A motor car is moving with a velocity of 108 km/h and it takes 4s to stop after the brakes are applied. Calculate the force exerted by the brakes on the motor car if its mass along with the passengers is 1000 Kg.
Answer» u = 108 km/h = 108 \(\times\frac{5}{18} = \) 30 m/s; m = 1000 kg ; v = 0 m/s F = m\((\frac{v\,-\,u}{t}) = 1000(\frac{0\,-\,30}{4})\) = -7500 kg ms^-2 = -7500 N

A motor car is moving with a velocity of 108 km/h and it takes 4s to stop after the brakes are applied. Calculate the force exerted by the brakes on the motor car if its mass along with the passengers is 1000 Kg.

Answer»

u = 108 km/h = 108 \(\times\frac{5}{18} = \) 30 m/s; m = 1000 kg ; v = 0 m/s

F = m\((\frac{v\,-\,u}{t}) = 1000(\frac{0\,-\,30}{4})\) = -7500 kg ms^-2 = -7500 N