A motercar with initial velocity 22 km/h attains velocity 94 km/h in 1/12 hour. If acceleration is uniform then find (i) Value of acceleration of car and (ii) Total distance travelled by car for attaining this velocity.

A motercar with initial velocity 22 km/h attains velocity 94 km/h in 1

1.	A motercar with initial velocity 22 km/h attains velocity 94 km/h in 1/12 hour. If acceleration is uniform then find (i) Value of acceleration of car and (ii) Total distance travelled by car for attaining this velocity.
Answer» INITIAL velocity = 22 kmphFinal velocity = 94 kmphTime interval = 1/12 hrTo Find :Acceleration of car and distance travelled by car in the given interval of time.Solution :❖ Acceleration is defined as the rate of change of velocity.It is a vector quantity having both magnitude as well as direction.SI unit : m/s²First of all we have to convert unit of velocity from kmph to mpsWe know that, 1 kmph = 5/18 mps• u = 22 kmph = 22 × 5/18 = 6.11 mps• v = 94 kmph = 94 × 5/18 = 26.11 mpsTime = 1/12 hr = 3600/12 = 300 s➙ v = u + atv denotes final velocityu denotes initial velocitya denotes accelerationt denotes time➙ 26.11 = 6.11 + 300a➙ 20 = 300a➙ a = 20/300➙ a = 0.067 m/s²♦ Distance covered by car :APPLYING 3rd equation of KINEMATICS;➠ v² - u² = 2as➠ (26.11)² - (6.11)² = 2(0.067) × s➠ 681.73 - 37.33 = 0.134 s➠ s = 644.4 / 0.134➠ s = 4809 m

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A motercar with initial velocity 22 km/h attains velocity 94 km/h in 1/12 hour. If acceleration is uniform then find (i) Value of acceleration of car and (ii) Total distance travelled by car for attaining this velocity.​

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A motercar with initial velocity 22 km/h attains velocity 94 km/h in 1/12 hour. If acceleration is uniform then find (i) Value of acceleration of car and (ii) Total distance travelled by car for attaining this velocity.