1.

A monochromatic light source of frequency `6xx10^(14)Hz` is emitting energy at the rate `2xx10^(-3)J//s`. Calculate the number of photons emitted per seconds by source.

Answer» Given that `v=6xx10^(14)Hz`
`P=Q=2xx10^(-3)J//s`
number of photons emitted per sec by the source.
`rArr n(P)/(nv)=(2xx10^(-3))/(6.62xx10^(-34)xx6xx10^(14))`
`=0.5035xx10^(-15)` per second.


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