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A monochromatic light source of frequency `6xx10^(14)Hz` is emitting energy at the rate `2xx10^(-3)J//s`. Calculate the number of photons emitted per seconds by source. |
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Answer» Given that `v=6xx10^(14)Hz` `P=Q=2xx10^(-3)J//s` number of photons emitted per sec by the source. `rArr n(P)/(nv)=(2xx10^(-3))/(6.62xx10^(-34)xx6xx10^(14))` `=0.5035xx10^(-15)` per second. |
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