A monoatomic gas undergoes a process given by 2dU + 3d W = 0, then wha

1.	A monoatomic gas undergoes a process given by 2dU + 3d W = 0, then what is the process
Answer» Solution :`dQ = dU + dW` `RARR dQ = dU - (2dU)/(3) =(dU)/(3) = (1)/(3) nC_(v)dT` `=(1)/(3)n.(3)/(2)RdT=(nRdT)/(2) rArr C=(1)/(n)(dQ)/(dT)=(R )/(2)` It is not ISOBARIC as C is not equal to `(5R)/(2)` It is not adiabatic as `c ne 0` It is not isothermal as `c ne oo` so itis an polytropic process.

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