1.

A mixture of N_(2) and H_(2) in the molar ratio1:3 attains equilibrium when 50% of the mixture has reacted , If P is the total pressure of the mixture , then partial pressure of NH_(3) formed is

Answer»

`P//2`
`P//3`
`P//4`
`P//6`

Solution :`{:(,N_(2),+,3 H_(2),hArr,2 NH_(3)),("Intial",1 " mole",,3 "moles",,0),("At eqm." ,1-x,,3-3x,,2 x):}`
But out of4 moles of the mixture , 2 moles have reacted and HENCE 2 moles are LEFT .
` :. (1-x) + ( 3-3x) = 2 OR4 x = 2 or 4 x = 2 or x = 0.5`
` :. " Total moles at equilibrium " `
` = (1-x) + (3-3x )+ 2 x `
` = 4 - 2 x = 4 - 1 = 3 `
No . of moles of `NH_(3)` at equilibrium = 2 x = 1
` :. p_(NH_(3)) = 1/3 xx P = P/3 `


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