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A mixture of N_(2) and H_(2) in the molar ratio1:3 attains equilibrium when 50% of the mixture has reacted , If P is the total pressure of the mixture , then partial pressure of NH_(3) formed is |
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Answer» `P//2` But out of4 moles of the mixture , 2 moles have reacted and HENCE 2 moles are LEFT . ` :. (1-x) + ( 3-3x) = 2 OR4 x = 2 or 4 x = 2 or x = 0.5` ` :. " Total moles at equilibrium " ` ` = (1-x) + (3-3x )+ 2 x ` ` = 4 - 2 x = 4 - 1 = 3 ` No . of moles of `NH_(3)` at equilibrium = 2 x = 1 ` :. p_(NH_(3)) = 1/3 xx P = P/3 ` |
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