A mixture of ethanol and propanol has vapour pressure of 290mm at 29oC. If mole fraction of ethanol is 0.65, then what will be its vapour pressure if vapour pressure of pure propanol is 210mm?

A mixture of ethanol and propanol has vapour pressure of 290mm at 29oC

1.	A mixture of ethanol and propanol has vapour pressure of 290mm at 29oC. If mole fraction of ethanol is 0.65, then what will be its vapour pressure if vapour pressure of pure propanol is 210mm?
Answer» since mole fraction of propanol is = 1- Xethanol therefore Xpropanol = 1-0.65 = 0.35 a/c Raoults LAW vapour PRESSURE of propanol (PP) = P°p × Xp = 210×0.35 = 73.5 MM