1.

A mixture of co and co2 has vapour density 20 at stp. 100 g of this mixture contains:

Answer»

Hey dear,

● Answer -
0.625 moles of CO
1.875 moles of CO2

EXPLANATION -
# Given-
Vapor density = 20

# Solution-
Molar WEIGHT of mixture = 2 × vapor density = 2 × 20 = 40

Let
x = mole fraction of CO
1-x = mole fraction of CO2

Therefore,
28(x) + 44(1-x) = 40
28x + 44 - 44x = 40
16x = 4
x = 0.25

No of moles of CO will be -
n1 = 0.25 × 100 / 40
n1 = 0.625 moles

No of moles of CO2 will be -
n2 = (1-0.25) × 100 / 40
n2 = 1.875 moles

Therefore, 100 g of mixture contains 0.625 moles of CO and 1.875 moles of CO2.

Hope this helps...



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