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Answer» Hey dear,
● Answer - 0.625 moles of CO 1.875 moles of CO2
● EXPLANATION - # Given- Vapor density = 20
# Solution- Molar WEIGHT of mixture = 2 × vapor density = 2 × 20 = 40
Let x = mole fraction of CO 1-x = mole fraction of CO2
Therefore, 28(x) + 44(1-x) = 40 28x + 44 - 44x = 40 16x = 4 x = 0.25
No of moles of CO will be - n1 = 0.25 × 100 / 40 n1 = 0.625 moles
No of moles of CO2 will be - n2 = (1-0.25) × 100 / 40 n2 = 1.875 moles
Therefore, 100 g of mixture contains 0.625 moles of CO and 1.875 moles of CO2.
Hope this helps...
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