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a mixture of 2 gases contains gas A with mol mass 40 and B with 80 and have vapour density 25.the mole% of B is |
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Answer» The % of B is 25%. It is now known that the relation between the vapour density and the molecular mass of a compound or mixture is given as FOLLOWS: M = 2 X VD So, molecular mass of the mixture is 50 units. Now, assuming that the % of B is x %, we can take % of A to be (100-x) %. Substituting the equation of the mass relation with the assumed mass percentages, we FIND that the percentage of B COMES out to be 25%. |
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