A mixture of 10 L of butane and propane was subjected to combustion and total volume of CO2 evolved was equal to 35 L. The volume of propane in litres in the mixture is Answer:

A mixture of 10 L of butane and propane was subjected to combustion an

1.	A mixture of 10 L of butane and propane was subjected to combustion and total volume of CO2 evolved was equal to 35 L. The volume of propane in litres in the mixture is Answer:
Answer» CO 2 (3×3=9)Butane-C 4 H 1 0+65O 2 →4CO 2 +5H 2 O3 liters of butane WOULD produce 12 liters of CO 2 ($$3\times 4 = 12$$)Liters of propane = XLiters of butane = YX+Y=33X+4Y=10Solve 2 simultaneous equations to get-Y = 12 MOLE propane and 1 mole butane.So the ratio is 2:1.Explanation:HERE IS YOUR ANSWER PLEASE MARK ME BRAINLIEST