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A mixture of 0.3 mole of H_(2) and 0.3 mole of I_(2) is allowed to react in a 10 lit vessel at 500^(@)C. If K_(C) of H_(2) +I_(2) |
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Answer» 0.15 mole `K_(C)=((2X // 10)^(2))/(((0.3Lx)/(10))^(2))=((2x)/(0.3-x))^(2)` `64=((2x)/(0.3-x))^(2) IMPLIES x=0.24` `:.` unreacted `I_(2)=0.3-0.24=0.06` |
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