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A microscope has an object and eyepiece of focal lenghts 5 cm and 50 cm respectively with tube length 30 cm. Find the magnificationof the microscope in the (i) near point and (ii) normal focusing. |
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Answer» Solution :`f_(0)=5cm=5XX10^(-2)m,f_(E)=50cm=50xx10^(-2)m,` `L=30cm=30xx10^(-2)m,D=25cm=25xx10^(-2)m` (i) The total magnification m in the near point focusing is, `m=m_(0)m_(e)=((1)/(f_(o)))(1+(D)/(f_(e)))` Substituting `m=m_(o)m_(e)=((30xx10^(-2))/(5xx10^(-2)))(1+(25xx10^(-2))/(50xx10^(-2)))=(6)(1.5)=9` (ii) The total magnification m innormal focusingis `m = m_(o)m_(e) = ((L)/(f_(o)))((D)/(f_(e)))` Substituting, `m=m_(o)m_(e)=((30xx10^(-2))/(5xx10^(-2)))((25xx10^(-2))/(50xx10^(-2)))=(6)(0.5)=3` |
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