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A meter bridge is set up as shown, to determine an unknown resistance `X` using a standard 10 ohm resistor. The galvanometer shows null point when tapping -key is at 52 cm mark. The end-corrections are 1 cm and 2 cm respectively for the ends A and B. The determine value of `X` is A. `10.2ohm`B. `10.6ohm`C. `10.8ohm`D. `11.1ohm` |
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Answer» `l_(1) = 52 + 1 = 53 cm` `l_(2) = 48 + 2 = 50 cm` `(l_(1))/(l_(2)) = (x)/(R) rArr (53)/(50) = (x)/(10)` `x = 10.6 Omega` . |
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