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A meter bridge is set up as shown, to determine an unknown resistance `X` using a standard 10 ohm resistor. The galvanometer shows null point when tapping -key is at 52 cm mark. The end-corrections are 1 cm and 2 cm respectively for the ends A and B. The determine value of `X` is A. `10.2 ohm`B. `10.6 ohm`C. `10.8 ohm`D. `11.1 ohm` |
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Answer» Correct Answer - b Using the condition for balanced Wheatstone bridge, we get `(X)/(10) = ((52+1)"cm")/((100- 52+2)"cm") = (53)/(50)` or `X = (53 xx 10)/(50) = 10.6 Omega` |
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