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A metallic sphere weighs `210g` in air, 180 g in water and 120 g in an unknown liquid. Find the density of metal and of liquid. |
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Answer» Correct Answer - C Relative density of metal `=("weight in air")/("change in weight of water")=(210)/(210-180)=7` `:.` Density of metal`=7g//cm^(2)` Change in weight in a liquid =upthrust in liquid `=(V_("solid")) (rho_("liquid"))g` or, `Delta w prop rho_(liquid)` `:. (Delta w_(l))/(Delta w_(w))=(rho_(l))/(rho_(w))` `rho_(l)=(Deltaw_(l))/(Deltaw_(w)) rho_(w)` `((210-120)/(210-180))(1)gm//cm^(3)` `=3g//cm^(3)` |
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