1.

A metallic sphere of mass M falls through glycerine with a terminal velocity v. If we drop a ball of mass 8M of same metal into a column of glycerine, the terminal velocity of ball will be

Answer»

2V
4v
8v
16v

Solution :`M=(4)/(3)pir^(3)RHO and 8M =(4)/(3)piR^(3)rho`,
`therefore R^(3)=8r^(3)` or `R=2R`
As `v prop r^(2)`
`therefore (v')/(v)=((R)/(r))^(2)=((2r)/(r))^(2)=4` or `v'=4v`


Discussion

No Comment Found