1.

A metallic rod breaks when strain produced is 0.2%. The Young's Modulus of the materials of the rod is .What should be its area of cross-section to support a load of 104N

Answer»

From Young’s Modulus FORMULAE:
Y = Fl’/Al
where L’ = 2l/1000
putting all the values we get,
7 x 10^9 = 10^4 * 2l/1000*A*l
solving we get,
A = 1/1400 m^2.



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