A metallic ion M^(2+) has an electronic configuration of 2, 8, 14 and the ionic weight is 56 amu. The number of neutrons in its nucleus is

A metallic ion M^(2+) has an electronic configuration of 2, 8, 14 and

1.	A metallic ion M^(2+) has an electronic configuration of 2, 8, 14 and the ionic weight is 56 amu. The number of neutrons in its nucleus is
Answer» 30 32 34 42 Solution :E.C. of `M^(2+) = 2, 8, 14` i.e., it has 24 electrons. HENCE, METAL atom M WOULD have electrons = 26 Hence, protons = 26, NEUTRONS `= A - Z = 56 - 26 = 30`