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A metallic disc of radius `r` is made of a material of negligible resistance and can rotate about a conducting horizontal shaft. A smaller non conducting disc of radius a is fixed onto the same shaft and has a massless cord wrapped around it, which is attached to a small object of mass `m` as shown. Two ends of a resistor of resistance `R` are connected to the perimeter of the disc and to the shaft by sliding contacts. The system is then placed into a uniform horizontal magnetic field `B` and the mass `m` is released. Find the terminal angular velocity with which the disc will rotate finally. (Take `r=10 cm `, `a=2cm`, `R=(1)/(100)Omega`, `B=0.2 T`, `m=50 gm`, `g=10m//s^(2)`) A. `200 rad//s`B. `300 rad//s`C. `100 rad//s`D. `10 rad//s` |
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Answer» At terminal stage, torque applied on the smaller disc by the rope `=mga` current to the disc `=(Bomega r^(2))/(2R)`(where `omega` is terminal angular velocity) torque applied by magnetic field `=(B^(2)omega r^(4))/(4R)` So, `(B^(2)omega r^(4))/(4R)=mga` `omega=100 rad//sec` |
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