a metalic wire of resistance r is cut into ten parts of equal length. they are then joined in parallal. what will be total resistance of this parallel combination.

a metalic wire of resistance r is cut into ten parts of equal length.

1.	a metalic wire of resistance r is cut into ten parts of equal length. they are then joined in parallal. what will be total resistance of this parallel combination.
Answer» The resistance of a conductor is DIRECTLY proportional to the length of the conductor. The resistance of the metallic wire, when it is cut into TEN parts of EQUAL length is R= 10R Two such pieces when joined in series, the equivalent resistance of these two parts=r+r=2r= 102R.Series resistance of two parts =2X 10R = 5 ′R 5 such elements are connected in parallel. Therefore the total resistance R ′will beR1 = R1 + R1+ R1 + R1 + R1 = R25Hence R ′ = 25R .

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a metalic wire of resistance r is cut into ten parts of equal length. they are then joined in parallal. what will be total resistance of this parallel combination.​

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a metalic wire of resistance r is cut into ten parts of equal length. they are then joined in parallal. what will be total resistance of this parallel combination.