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A metal wire of cross-sectional area `1m m^(2)` contains `5xx10^(22)` electrons per `cm^(3)` . If the electrons move along the wire with average drift velocity `1m m//s`, then the current in the wire is (`e=1.6xx10^(-19)C`)A. 8AB. 4AC. 2AD. 1A |
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Answer» Correct Answer - A `v_(d)=(I)/(n A e)` `:.I=v_(d) nA e` `=1xx10^(-3)xx5xx10^(22)xx10^(6)xx10^(-6)xx1.6xx10^(-19)` `= 8A` |
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