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A metal rod of Young's modulus 2 xx 10 ^(10) Nm ^(-2),undergoes longitudinal strain of 1%, the potential energy per unit volume stored in rod is ....... Jm^(-3). |
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Answer» `10 ^(6)` `u = 1/2 xx` stress `xx` STRAIN `=1/2 xx` Young modulus `xx("strain")^(2)` `(because` stress `= Y xx` strain) `=1/2 xx Y ((Delta l )/(l )) ^(2) ` ` therefore u = 1/2 xx 2 xx 10 ^(10) xx (0.01) ^(2)` `therefore u = 1 xx 10 ^(6)` `=10^(6) Jm^(-3)` |
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