1.

A metal rod of Young's modulus 2 xx 10 ^(10) Nm ^(-2),undergoes longitudinal strain of 1%, the potential energy per unit volume stored in rod is ....... Jm^(-3).

Answer»

`10 ^(6)`
`10^(8)`
`2xx10 ^(6)`
`2xx10^(8)`

SOLUTION :The potnetial energy PER unit volume
`u = 1/2 xx` stress `xx` STRAIN
`=1/2 xx` Young modulus `xx("strain")^(2)`
`(because` stress `= Y xx` strain)
`=1/2 xx Y ((Delta l )/(l )) ^(2) `
` therefore u = 1/2 xx 2 xx 10 ^(10) xx (0.01) ^(2)`
`therefore u = 1 xx 10 ^(6)`
`=10^(6) Jm^(-3)`


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