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A metal rod of length 'L' and maws 'm' is pivoted at one end A thin disc of mass 'M' and radius 'R' ( |
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Answer» Restoring torque in case A = Restoring torque in case B In case A disc is not free to rotate about itscentre hence it has to change its orientation during the oscillation and its moment of inertia as a disc will be counted. But in second case disc will oscillate without changing its orientation andit will be just like a POINT mass attached at theend of rod. We can understand that moment of inertia in case A will be more than in case B. Frequency is INVERSELY proportional to square root of moment of inertia, hence we can understand that option (d) is ALSO correct. |
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