A metal plate of area 1×10−4m2 is illuminated by a radiation of intensity 16 mW/m2 . The work function of the metal is 5 eV. The energy of the incident photons is 10 eV and only 10% of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy respectively, will be[1eV=1.6×10−19J]

A metal plate of area 1×10−4m2 is illuminated by a radiation of int

1.	A metal plate of area 1×10−4m2 is illuminated by a radiation of intensity 16 mW/m2 . The work function of the metal is 5 eV. The energy of the incident photons is 10 eV and only 10% of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy respectively, will be[1eV=1.6×10−19J]
Answer» A metal plate of area $1 \times 10^{- 4} m^{2}$ is illuminated by a radiation of intensity $16 {mW/m}^{2}$ . The work function of the metal is $5 eV$ . The energy of the incident photons is $10 eV$ and only $10 %$ of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy respectively, will be $[1 eV = 1.6 \times 10^{- 19} J]$

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