1.

A metal piece of 50 g specific heat 0.6 cal/gºC initially at 120ºC is dropped in 1.6 kg of water at 25ºC. Find the final temperature or mixture.

Answer»

m1c1 (θ1 – θ) = m2c2 (θ – θ2) 

∴ c2 = 1 cal/gmºC 

∴ 50 × 0.6 × (120 – θ) 

= 1.6 × 103 × 1 × (θ – 25) 

θ = 26.8ºC



Discussion

No Comment Found