A metal has a fcc lattice. The edge length of the unit cell is 404 pm.The density of the metal is 2.72 "g cm"^(-3). The molar mass of the metal is (N_A , Avogadro's constant =6.02xx10^23 "mol"^(-1))

A metal has a fcc lattice. The edge length of the unit cell is 404 pm.

1.	A metal has a fcc lattice. The edge length of the unit cell is 404 pm.The density of the metal is 2.72 "g cm"^(-3). The molar mass of the metal is (N_A , Avogadro's constant =6.02xx10^23 "mol"^(-1))
Answer» `"40 g mol"^(-1)` `"30 g mol"^(-1)` `"27 g mol"^(-1)` `"20 g mol"^(-1)` SOLUTION :Density , `rho=(ZxxM)/(a^3xxN_Axx10^(-30))` `therefore 2.72=(4xxM)/((404)^3xx(6.02xx10^23)xx10^(-30))` or `M=(2.72xx(404)^3xx6.02xx10^23xx10^(-30))/4` `=27 "g mol"^(-1)`