A metal has a fcc lattice. The edge length of the unit cell is 404 pm. The density of the metal is 2.72 g cm^(-3)? The molar mass of the metal is (N_(A)" Avogadro's constant" = 6.02times10^(23) mol^(-1))

A metal has a fcc lattice. The edge length of the unit cell is 404 pm.

1.	A metal has a fcc lattice. The edge length of the unit cell is 404 pm. The density of the metal is 2.72 g cm^(-3)? The molar mass of the metal is (N_(A)" Avogadro's constant" = 6.02times10^(23) mol^(-1))
Answer» `40" g "MOL^(-1)` `30" g "mol^(-1)` `27" g "mol^(-1)` `20" g "mol^(-1)` SOLUTION :`"Density " rho = (ZtimesM)/(a^(3)timesN_(A)times10^(-30))` `therefore 2.72 = (4timesM)/((404^(3))times(6.02times10^(23))times10^(-30))` `therefore M = (2.72times(404)^(3)times(6.02times10^(23))times10^(-30))/4` =`27 g"" mol^(-1)`