a metal forms two oxides. The higher oxide contains 80% metal. 0.72g of the lower oxide gave 0.8g of the higher oxide when oxidised.show that the data illustrate the law of multiple proportions.

a metal forms two oxides. The higher oxide contains 80% metal. 0.72g o

1.	a metal forms two oxides. The higher oxide contains 80% metal. 0.72g of the lower oxide gave 0.8g of the higher oxide when oxidised.show that the data illustrate the law of multiple proportions.
Answer» higher OXIDE 0.80 gms : 0.64 gm of metal in the higher oxide.Thus before oxidation, there is 0.64 gm of metal in the lower oxide.So there is 0.72 gms - 0.64 gms = 0.08 gms of oxygen in lower oxide. and 0.80 - 0.64 = 0.16 gms of oxygen in lower oxide. The proportions of metal : oxygen in both OXIDES are: 0.64 : 0.08 = 8 : 1 0.64 : 0.16 = 8 : 2So in the higher oxide there is DOUBLE the amount of oxygen as COMPARED to the lower oxide. The content of oxygen that reacts with metal are in the integer ratio : 1 : 2.