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A metal disc of radius a rotates with a constant angular velocity `omega` about its axis. The potential difference between the center and the rim of the disc is `("m = mass of electron, e = charge on electro")`A. (a) `(momega^(2)a^(2))/(e)`B. (b) `(1)/(2)(momega^(2)a^(2))/(e)`C. ( c) `(e omega^(2)a^(2))/(2m)`D. (b) `(eomega^(2)a^(2))/(m)` |
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Answer» Correct Answer - B ( b) Let `E` be the electric field at a distance `r` from the centre of the disc. Then `eE = m omega^(2)r` or `E = (m omega^(2)r)/(e)` ``:.` P.D. = int_(r=0)^(r=a)Edr` `=int_(0)^(a)(m omega^(2)a^(2))/(2e)` |
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