A metal cube of edge 12 cm is melted and formed into three smaller cub

1.	A metal cube of edge 12 cm is melted and formed into three smaller cubes. If the edges of the two smaller cubes are 6 cm and 8 cm, find the edge of the third smaller cube.
Answer» Given details are, Edge of metal cube (volume) = 12cm Edge of smaller two cubes = 6cm, 8cm Let edge of third cube be ‘a’ cm So, Volume of metal cube = sum of volume of three small cubes 12³ = 6³ + 8³ + a³ 1728 = 216 + 512 + a³ a³ = 1728 – 216 – 512 = 1000 a = ³√1000 = 10cm ∴ Edge of third smaller cube is 10 cm.

A metal cube of edge 12 cm is melted and formed into three smaller cubes. If the edges of the two smaller cubes are 6 cm and 8 cm, find the edge of the third smaller cube.

Answer»

Given details are,

Edge of metal cube (volume) = 12cm

Edge of smaller two cubes = 6cm, 8cm

Let edge of third cube be ‘a’ cm

So,

Volume of metal cube = sum of volume of three small cubes

12³ = 6³ + 8³ + a³

1728 = 216 + 512 + a³

a³ = 1728 – 216 – 512

= 1000

a = ³√1000

= 10cm

∴ Edge of third smaller cube is 10 cm.