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A metal coin is at bottom of a beaker filled with a liquid of refractive index = 4/3 to height of 6 cm. To an observer looking from above the surface of liquid, coin will appear at a depth (a) 1.5 cm (b) 6.75 cm (c) 4.5 cm (d) 7.5 cm |
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Answer» the APPARENT distance=d^=d(u2/u1) d^=6(3/4)here u1=water refractive INDEX u2 =AIR refractive indexd^=9/2=4.5cmhope so helpfulgood QUESTION keep it up! |
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