1.

A metal coin is at bottom of a beaker filled with a liquid of refractive index = 4/3 to height of 6 cm. To an observer looking from above the surface of liquid, coin will appear at a depth (a) 1.5 cm (b) 6.75 cm (c) 4.5 cm (d) 7.5 cm

Answer»

the APPARENT distance=d^=d(u2/u1) d^=6(3/4)here u1=water refractive INDEX u2 =AIR refractive indexd^=9/2=4.5cmhope so helpfulgood QUESTION keep it up!



Discussion

No Comment Found

Related InterviewSolutions