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A metal bar 2.5 m long extends by 0.05 mm when a tensile load is applied to it. Determine (a) the strain, (b) the percentage strain. |
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Answer» (a) Strain \(\varepsilon\) = \(\cfrac{extension}{original\, lengh}\) = \(\cfrac{0.05\,mm}{2.5\times10^3\,mm}\) = \(\cfrac{0.05}{2500}\) = 0.00002 (b) Percentage strain = 0.00002 100 = 0.002% |
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