1.

A metal bar 2.5 m long extends by 0.05 mm when a tensile load is applied to it. Determine (a) the strain, (b) the percentage strain.

Answer»

(a) Strain \(\varepsilon\) = \(\cfrac{extension}{original\, lengh}\) = \(\cfrac{0.05\,mm}{2.5\times10^3\,mm}\)

\(\cfrac{0.05}{2500}\) = 0.00002

(b) Percentage strain = 0.00002  100 = 0.002%



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