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A metal (atomic mass 50) has a body centred cubic crystal structure. The density of the metal is `5.96 "g cm"^(-3)`. Find the volume of the unit cell (`N_O=6023xx10^23 "atoms mol"^(-1)`) |
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Answer» Correct Answer - `2.786xx10^(-23) cm^3` Mass of the unit cell = Mass of one atom x No. of atoms present in the unit cell `=(50/(6.023xx10^23)g)xx2` [For BCC, Z=2] Volume of the unit cell=`"Mass"/"Density"=(50xx2)/(6.023xx10^23)gxx1/(5.96 g cm^(-3))=2.786xx10^(-23) cm^(3)` |
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