1.

A massless spring, having force constant k, oscillates with a frequency n when a mass m is suspended from it. The spring is cut into two equal halves and a mass 2m is suspended from one of the parts. The frequency of oscillation will now be………….

Answer»

n
`nsqrt(2)`
`(n)/(sqrt(2))`
2n

Solution :`n=(1)/(2pi)sqrt((K)/(m)),n.=(1)/(2)sqrt((2)/(2))=n`


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