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A mass of 2 kg is moving along a circular path of radius 1 m. If the mass moves with 300 revolutions per minute, its kinetic energy would be:1. 250 π22. 25 π23. 200 π24. 100 π2 |
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Answer» Correct Answer - Option 4 : 100 π2 Given: Mass (m) = 2 kg Radius (r) = 1 m v = 300 revolution/min Formula used: Angular speed (w) = 2πv Linear speed (v) = wr Kinetic energy = 1/2 mv2 Calculation: v = 300/60 = 5 revolution/min Angular speed = 2π × 5 = 10π Linear speed (v) = wr = 10π × 1 = 10π Kinetic energy = 1/2 × 2 × 10π × 10π ⇒ 1/2 × 2 × 100 π2 ⇒ 100 π2 ∴ Required kinetic energy is 100 π2 |
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