A mass of 10 kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle 45∘ at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is (g=10 ms−2)

A mass of 10 kg is suspended vertically by a rope from the roof. When

1.	A mass of 10 kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle 45∘ at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is (g=10 ms−2)
Answer» A mass of $10 kg$ is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle $45^{\circ}$ at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is ( $g = 10 {ms}^{- 2}$ )

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A mass of 10 kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle 45∘ at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is (g=10 ms−2)

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